Y=3x^2+42

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Solution for Y=3x^2+42 equation: 



=3Y^2+42

We move all terms to the left:

-(3Y^2+42)=0

We get rid of parentheses

-3Y^2-42=0

a = -3; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·(-3)·(-42)
Δ = -504
Delta is less than zero, so there is no solution for the equation

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